![]() Being new to json, and having not touched php in some time I'm having a hard time formatting the loop properly and grabbing the appropriate data. The issue I'm having is trying to wrap this in a foreach loop to spit out a list item for each item in the json feed. Now obviously this will only grab the information in the second array slot and I'm aware that there is a more efficient way to write the list items, without jumping in and out of php, and that will be cleaned up shortly. I have created a javascript file with a json feed in it and have successfully decoded it using php and can now access the data (one item at a time) but I'm hitting a snag when trying to iterate over it and spit out list items using all of the data. There is no need to decode it, convert into. Iterate over it with foreach.I've been working with json for the first time and php for the first time in a long time and I've hit a wall regarding the two. By default, MySQL comes with the support of JSON type and you can use it to manage your JSON data as it is. ![]() $json = 'Įcho $toppings //Chocolate with Sprinkles You access the elements of one of these arrays the same way you would for any other array, e.g. Puedes ejecutar los procedimientos siguientes: A. JSON can represent any arbitrary hierarchical data structure, for which there is not really any equivalent data type in MySQL. parse: none The relevant code part:- 1) Results of PHP array print, > 2) Results of JSON parse: none
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